Talk:Use familiar

This always seems to return false for me, can anyone confirm?
--Slyz 20:56, 9 April 2010 (UTC)

> ash use_familiar($familiar[sandworm])

Putting Mexicana the Hovering Sombrero back into terrarium...

Taking Hecho en Mexico the Baby Sandworm out of terrarium...

Returned: true

I assume that the ash command should be enough to check return value; correct me if I'm wrong. --Heeheehee 21:03, 9 April 2010 (UTC)

I'll have to recheck after RO, but here is what I was getting (doing things slightly differently):

> ash print( use_familiar($familiar[slimeling]) )

Putting Dusty the Baby Sandworm back into terrarium...

Taking Yuk the Slimeling out of terrarium...

false

Returned: void

--Slyz 03:33, 10 April 2010 (UTC)

Huh. Using that method, I get:

> ash print( use_familiar($familiar[sombrero]) )

Putting Hecho en Mexico the Baby Sandworm back into terrarium...

Taking Mexicana the Hovering Sombrero out of terrarium...

true

Returned: void

--Heeheehee 07:51, 10 April 2010 (UTC)

I'm also seeing expected behavior; true most of the time, false if I try a familiar I don't have. --StDoodle (#1059825) 14:52, 10 April 2010 (UTC)

I find the syntax as described on this page confusing. With other functions I do not have to specify the datatype, for example:
outfit($string[Backup]);
outfit("Backup");
both work identically. However, use_familiar("hobo");
returns the error "Function 'use_familiar( string )' undefined..."
This just happened to be the first function I looked up on this wiki, and if the discussion with examples had not been here, I don't think I would have worked it out at all.--RogerMexico 12:04, 25 September 2010 (UTC)